回答你的第一個(gè)問(wèn)題。 {/Qg4pc!
假設(shè)你的變焦鏡頭有三個(gè) zoom positions,物在無(wú)限遠(yuǎn) 8%#pv}
(1) zoom 1, 2, 3 的焦距為分別為 100, 200, 300 `HV~.C
(2) 三個(gè) zoom positions 的鏡頭第一面至成像面長(zhǎng)度要完全一樣 9Pjw<xt
(3) 鏡頭第一面至成像面長(zhǎng)度要 <= 130 mm XyrQJ}WR|
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那麼優(yōu)化程式可寫成如下: H?$gHZPI
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! 設(shè)定各 zoom 之焦距 100, 200, 300 dvPlKLp
efy s1..i z1 = 100 'FN+BvD
efy s1..i z2 = 200 SioP`*,}
efy s1..i z3 = 300 qg9VK'3o
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! 鏡頭第一面至成像面長(zhǎng)度要 <= 130 mm p?e-`xs
@OAL == (oal s1..i z1); @OAL <= 130 4>}qdR1L4
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! zoom 2 及 zoom 1 鏡頭長(zhǎng)度相等 3}gf%U]L
@OAL_Z21 == (oal s1..i z2) - (oal s1..i z1); @OAL_Z21 = 0 %Qy9X+N:
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! Zoom 3 及 zoom 1 鏡頭長(zhǎng)度相等 MVXy)9q
@OAL_Z31 == (oal s1..i z3) - (oal s1..i z1); @OAL_Z31 = 0 3JXKpk?
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